c^2-5cy-50y^2=

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Solution for c^2-5cy-50y^2= equation: 


Simplifying
c2 + -5cy + -50y2 = 0

Reorder the terms:
-5cy + c2 + -50y2 = 0

Solving
-5cy + c2 + -50y2 = 0

Solving for variable 'c'.

Factor a trinomial.
(c + -10y)(c + 5y) = 0


Subproblem 1
Set the factor '(c + -10y)' equal to zero and attempt to solve:

Simplifying
c + -10y = 0

Solving
c + -10y = 0

Move all terms containing c to the left, all other terms to the right.

Add '10y' to each side of the equation.
c + -10y + 10y = 0 + 10y

Combine like terms: -10y + 10y = 0
c + 0 = 0 + 10y
c = 0 + 10y
Remove the zero:
c = 10y

Simplifying
c = 10y

Subproblem 2
Set the factor '(c + 5y)' equal to zero and attempt to solve:

Simplifying
c + 5y = 0

Solving
c + 5y = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5y' to each side of the equation.
c + 5y + -5y = 0 + -5y

Combine like terms: 5y + -5y = 0
c + 0 = 0 + -5y
c = 0 + -5y
Remove the zero:
c = -5y

Simplifying
c = -5y
Solution
c = {10y, -5y}

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